Help talk:Parser functions in templates

I think there's a logical error here. It's easiest to see in the table at the bottom. In sample 1, is true for both being defined and for being not defined. How can it both be defined and not defined? -Khono
 * I think it is right. If you call, then both and  will return "bar" (in template:foo), why the #if statement treat both as true. --79.136.98.249 23:13, 1 September 2009 (UTC)

White spaces
Is there any parser function that strip leading and tailing white spaces, or one that change them into "%20" or "_"? I try to make a template that includes a link to wikipedia.

--Petter Källström, 79.136.98.249 23:13, 1 September 2009 (UTC)
 * givs: See phoo Wikipedias article - NOK (.../wiki/).
 * givs: See Wikipedias article - OK (.../wiki/phoo).
 * givs: See bar Wikipedias article - NOK (.../wiki/phoo).
 * givs: See Wikipedias article - NOK (../wiki/Parser).