Extension talk:RegexParserFunctions

Could you put more samples of use here, Please. For example, what are the different using between match and replacement. --Roc michael 12:17, 15 June 2007 (UTC)


 * Hi Roc! More detailed examples and usage instructions are availble on the RegexParserFunctions Project HomePage. --Jimbojw 04:42, 16 June 2007 (UTC)


 * Thank for your help, Jimbojw.--Roc michael 07:10, 16 June 2007 (UTC)

I really love this extension!

I also have an improvement idea:

replacing like  would be much more usefull if it would be possible to do something with the replace string $1. For example. Certainly $1 as variable for such operations wouldn't be a good variable name because it also could be possible that in the match string is a $1. In this case we would get a problem. Perhaps you could make this work as variable for wikis with variable extension like: This would offer much new possiblities like run another regex over the matches. --Danwe 20:25, 22 February 2009 (UTC)

Helpful examples
I think it could be helpful if everybody who wrote a regex which is generally helpful adds it here. I Wrote one which dissolves all links inside a given string:

 

Example: " text text linktext and link " is going to be "text text linktext and link" --Danwe 22:15, 22 February 2009 (UTC)

Remove Category links
%\[\[Category?(?(?=[^\[\]\|]*\|)[^\[\]\|]*\||)([^\[\]]*)\]\]\n%

this removes cat links like. But it doesn't work if the category name includes : like in. How would I do that? Big thanks! --Subfader 20:32, 5 July 2009 (UTC)
 * /\[\[Category:.*\]\]\s*/s --Subfader 00:09, 8 July 2009 (UTC)

Doesn't work in 1.16alpha
Maybe you can have a look now already before everyone using this extension will come here ;) --Subfader 00:09, 8 July 2009 (UTC)
 * Using Extension:RegexFunctions instead :) --Subfader 22:45, 11 July 2009 (UTC)

New function for array regex (regexall)
I created a function regexall to get all matches of a regex. It returns all matches separated so you could use the result with the array extension for example. Replacing or getting some parts from brackets only is not possible yet. Please feel free to implement new features as well or to improve my code.

The function is based on the original regexParserFunction so I post it here for you as well:

--Danwe 14:02, 1 December 2009 (UTC)