Help:Parser functions in templates/ru

When applying ParserFunctions to template parameters, a pipe symbol ("|") may be used to provide a default value, which is used when a parameter is not defined. Used in an #if parser function, the unexpanded text from the undefined parameter will evaluate as true, which may be an unexpected result.


 *  


 * Пример A:  


 * Результат: 


 *  


 * Пример B:  


 * Результат: 

The second usage ( , sample B) with present empty default is often the desired way to handle situations where a parameter exists, but is comprised only of empty space.

Testing and passing undefined parameters
One way to test whether a parameter was specified in a template call is thus:


 *  

In rare cases, a template behaves differently when a parameter is unspecified compared to when it is specified but empty. When this template is used by a wrapper template (which uses the same set of named parameters), one way to ensure undefined parameters remain undefined is as follows (the technique also works with numbered parameters):

Note that the wrapped_template</tt> receives a specified but empty normal_parameter</tt> in two cases: when normal_parameter</tt> is specified and empty, and when normal_parameter</tt> is unspecified (because the default empty value is then specified by the wrapper template).

By contrast, the wrapped_template</tt> receives a specified sensitive_parameter</tt> only when it is indeed specified, because the #if</tt> changes the wrapped_template</tt> parameter name to « sensitive_parameterNULL</tt> » when sensitive_parameter</tt> is undefined.

Note also that wrapped_template</tt> receives a specified and empty sensitive_parameter</tt> only when the wrapper template receives a specified and empty sensitive_parameter</tt>. Of course, one must make sure the suffixed wrapped_template</tt> parameter name is meaningless to the wrapped_template</tt> for this to work properly.

См. также

 * Extension:Loops#forargs
 * Extension:Loops#forargs
 * Extension:Loops#forargs